Mostrando entradas con la etiqueta Hypernatremia. Mostrar todas las entradas
Mostrando entradas con la etiqueta Hypernatremia. Mostrar todas las entradas

domingo, 20 de febrero de 2011

Hypernatremia, Liquids and electrolites Manual (Constain, Alfred)

Hypernatremia means serum Na >145 mmol /ml. Severe hypernatremia >160 mmol/ml has a mortality rate of 75%.

Comprehense three categories:
1. Normovolemic hypernatremia
2. Hypervolemic Hypernatremia
3. Hypovolemic Hypernatremia

1. Normovolemic hypernatremia: It can occur in a wide spectrum of entities that cross since the insipid diabetes to overhydration.

2. Hypervolemic Hypernatremia: Occur principally in the hyperosmolar saline solutions context.

3. Hypovolemic Hypernatremia: Is the most comun, can occur in insipid diabetes, chronic renal failure, deshydration, shock.

Like general rule the sodium reposition can't be >10mmol/L in 24 hours and can't be superior to 0.5mEq/h.

So there are two formules to correct the sodium in hypernatremia:

1. Na plasma variation= ([Na] in the solution available - [serum Na]) / (Percentage of body water +1)

2. Na plasma variation= ([Na + K] in the solution available - [serum Na] / (Percentage of body water)

[Na] in the solution available= For example, the normal saline solution has 154mEq/L. 0.2% saline solution has 34 mEq/L. Normally, the reposition of water in hypernatremia is performed with 0.2% and 0.45% saline solution.

Percentage of body water= Men: 0.6*weight in Kg , Women: 0.5*weight in Kg

Example

A 65 yo man arrives to emergency department with HR:122bpm, AP: 120/75 mmhg, RR: 18 bpm, weight: 72Kg. [Na]= 162. Oral mucose was dry. The final diagnose is Pulmonary tromboembolism. ¿How do you correct this severe hypernatremia?

Percentage of body water= 43.2L
If we use a 5% dextrose solution, the [Na]= 0 mEq/L

Na plasma variation= ( [0] - 162) / (43.2 + 1) = 3.67 mEq

The value that we are going to replace is 3.67mEq/L, but we got to replace it till 10mEq/24h, hence 10/3.67= 2.62 L 5% of dextrose, wich is 113,5ml /h. After the first date of replacement we can perform it at 1mEq/h (i.e second day)